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发表于 14-7-2007 11:23 AM
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my school organic already finish and inorganic i will learn it this sunday...
n the physical have one topic my school teacher left it to behind...
that is the phase equilibrium...
[ 本帖最后由 zxteh 于 14-7-2007 11:26 AM 编辑 ] |
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发表于 14-7-2007 11:29 AM
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nikuang04 Which school do u from...
can u add me in MSN...
my MSN is [email protected]...
may b we can discuss more chemistry question in MSN |
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发表于 14-7-2007 11:31 AM
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Write out all the shape in bonding? |
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发表于 14-7-2007 06:00 PM
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Linear
Trigonal planar
Tetrahedral
Trigonal pyramidal
V-shaped
Trigonal bipyramidal
Seesaw-shaped
T-shaped
Octahedral
Square pyramidal
Square planar |
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发表于 14-7-2007 07:01 PM
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原帖由 zxteh 于 14-7-2007 11:29 发表 
nikuang04 Which school do u from...
can u add me in MSN...
my MSN is [email protected]...
may b we can discuss more chemistry question in MSN
我是槟城的
已经加入你
很高兴认识你
你好像是拿高数T的喔
Electronic structure:
calculate the frequency of the second line in balmer series.
given Rh=1.097 X 10^7 |
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发表于 16-7-2007 11:35 PM
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原帖由 huhuxboy 于 14-7-2007 06:00 PM 发表 
Linear
Trigonal planar
Tetrahedral
Trigonal pyramidal
V-shaped
Trigonal bipyramidal
Seesaw-shaped
T-shaped
Octahedral
Square pyramidal
Square planar
how about the square bipyramidal...
r u forget it...?
please take notes |
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发表于 16-7-2007 11:37 PM
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原帖由 nikuang04 于 14-7-2007 07:01 PM 发表
我是槟城的
已经加入你
很高兴认识你
你好像是拿高数T的喔
Electronic structure:
calculate the frequency of the second line in balmer series.
given Rh=1.097 X 10^7
By Rdyberg Equation : 1/A = Rh (1/n^2 - 1/m^2) where A=wave length,n=2,m=4
==>1/A = (1.097x10^7)(1/4-1/16) ==> A =486.2 nm
from v = f A (v=speed of light,f=frequency)
==> f = v/A = (3.00x10^8)(486.2x10^(-9)) = 6.17 x 10^14Hz
is it correct?
[ 本帖最后由 zxteh 于 16-7-2007 11:46 PM 编辑 ] |
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发表于 16-7-2007 11:45 PM
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Why Be(OH)2 and BeO salts cannot be hydrolysed while the salts like BeNO3 can be hydrolysed? |
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发表于 16-7-2007 11:52 PM
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原帖由 zxteh 于 16-7-2007 23:45 发表 
Why Be(OH)2 and BeO salts cannot be hydrolysed while the salts like BeNO3 can be hydrolysed?
你的这题是哪一课的？inorganic的吗？
麻烦各位来回答
原帖由 zxteh 于 16-7-2007 23:37 发表
By Rdyberg Equation : 1/A = Rh (1/n^2 - 1/m^2) where A=wave length,n=2,m=4
==>1/A = (1.097x10^7)(1/4-1/16) ==> A =486.2 nm
from v = f A  (v=speed of light,f=frequency)
==> f = v/A =  ...
全对
balmer series 是 transition of photons from higher energy levers to n=2
second line involves the transition of n=4 to n=2
再来：
The periodic table:
Explain why the atomic radius of the elements decreases with increasing proton number for elements in period 3.
[ 本帖最后由 nikuang04 于 16-7-2007 11:54 PM 编辑 ] |
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发表于 17-7-2007 02:25 PM
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原帖由 zxteh 于 16-7-2007 11:35 PM 发表
how about the square bipyramidal...
r u forget it...?
please take notes
square bipyramidal 是 octahedral, 不是吗？？？
[ 本帖最后由 huhuxboy 于 17-7-2007 02:36 PM 编辑 ] |
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发表于 17-7-2007 02:34 PM
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原帖由 nikuang04 于 16-7-2007 11:52 PM 发表
你的这题是哪一课的？inorganic的吗？
麻烦各位来回答
全对
balmer series 是 transition of photons from higher energy levers to n=2
second line involves the transition of n=4 to n=2
...
Across the 3rd period of the periodic table,the shielding effect of the inner shells remains constant as the electrons are added to the outermost quatum shell. Moreover, the proton numberincreases as the protons are added into the nuclues causing theeffective nuclear charge increase. Therefore its attraction for the outermost electrons increases. Thus, the outermost electrons are pulled in closer to the nucleus. Hence the atomic radius decreases across a period. |
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发表于 18-7-2007 03:50 PM
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原帖由 huhuxboy 于 17-7-2007 02:25 PM 发表 
square bipyramidal 是 octahedral, 不是吗？？？
square bipyramidal n octahedral are totally different...
please take notes... |
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发表于 18-7-2007 03:52 PM
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发表于 18-7-2007 06:25 PM
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原帖由 huhuxboy 于 17-7-2007 14:34 发表
Across the 3rd period of the periodic table,the shielding effect of the inner shells remains constant as the electrons are added to the outermost quatum shell. Moreover, the proton numberin ...
太好了
全对
原帖由 zxteh 于 18-7-2007 15:50 发表
square bipyramidal n octahedral are totally different...
please take notes...
octahedral就是上面一个金字塔形，下面一个金字塔形（2个金字塔的base连在一起）
所以也可以说是square bipyramidal，不是吗？
6个bonding pairs，没有lone pair就是octahedral
如果octahedral不是square bipyramidal，那么后者有几个bonding pairs几个lone pairs呢？
再来！！
Ionisation energy is the minimum energy required to remove 1 mole of electron of 1 mole of gaseous atoms in the ground state.
Give the factors that affect the value of ionisation energy.
[ 本帖最后由 nikuang04 于 18-7-2007 06:31 PM 编辑 ] |
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发表于 19-7-2007 02:23 PM
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factors that affect the value of ionisation energy:
1. size of atom
2. effective nuclear charge
3. screening effect of inner electrons |
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发表于 19-7-2007 02:25 PM
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我赞同nikuang04 所说的 octahedral and square bypiramidal refer to the same structure.
如果不同，zxteh友可以解释一下他们的区别吗？？？
多谢
[ 本帖最后由 huhuxboy 于 19-7-2007 02:29 PM 编辑 ] |
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发表于 19-7-2007 03:25 PM
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Why Be(OH)2 and BeO salts cannot be hydrolysed while the salts like BeNO3 can be hydrolysed?
why never have people solve my question...
how about u nikuang 04 |
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发表于 19-7-2007 03:32 PM
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发表于 19-7-2007 06:07 PM
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发表于 21-7-2007 04:53 PM
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