查看: 814|回复: 4
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php, 为什么????
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为什么当这段code 加进去html 时,load page 时就空白的?
<?php
session_start();
if($_SESSION['validuser'] != 'Y'){
echo "You are invalid user, ";
echo "<p><a href='index.php'>please login.</a></p>";
window_close();
}
$me = $_SERVER['PHP_SELF'] ;
$cus = $_POST["txtcus"];
$connection = mysql_connect("localhost","root","3361009");
$db = "ACC";
mysql_select_db($db, $connection) or die("Could not open $db");
$query = "SELECT * FROM ARMAS WHERE ARCODE LIKE '$cus%'";
$result = mysql_query($query);
$color = 0;
while($row = mysql_fetch_array($result)){
if($color == 0 ) {
$table = $table."<tr BGCOLOR='#C0C0C0'><td>".$row['ARCODE']."</td><td>".$row['ARNAME']."</td>;
$color = 1;
}
else {
$table = $table."<tr BGCOLOR='#FFFF00'><td>".$row['ARCODE']."</td><td>".$row['ARNAME']."</td>;
$color = 0;
}
}
mysql_close();
?> |
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发表于 23-6-2006 12:33 PM
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window_close();没有这function叻 |
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发表于 23-6-2006 12:34 PM
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你好像没有把td的内容注入html stream。
意思是我认为你需要再while loop 后加
echo $table; |
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发表于 27-6-2006 10:04 AM
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是不是跟本就选不到record所以就空白罗?!因为你写的coding说明有record才会跑table那边的coding,若没有record就不会跑了直接跳过。我看到sql好像有问题叻,试试这行
$query = "SELECT * FROM ARMAS WHERE ARCODE LIKE '".$cus."%'"; |
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发表于 28-6-2006 04:22 PM
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<table>和</table>呢?
试看在table tag里加border="1"看看有没有任何线条?
搂主,你解决了问题没有? |
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